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	<title>Comments on: LED Gloves</title>
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	<link>http://www.neufeld.newton.ks.us/electronics/?p=129</link>
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		<title>By: Keith Neufeld</title>
		<link>http://www.neufeld.newton.ks.us/electronics/?p=129&#038;cpage=1#comment-22101</link>
		<dc:creator>Keith Neufeld</dc:creator>
		<pubDate>Wed, 06 Aug 2008 00:11:00 +0000</pubDate>
		<guid isPermaLink="false">http://www.neufeld.newton.ks.us/electronics/?p=129#comment-22101</guid>
		<description>Zaid, the 4xAAA pack will be great for this -- it&#039;ll give you a lot longer life than the little coin cell I used.

Okay, let&#039;s figure out the resistor.  First we need the battery voltage.  I&#039;m going to assume you&#039;ll be using NiMH rechargeables, both because you&#039;ll be playing with this a lot and because they&#039;re better for the environment.  They&#039;re nominally 1.2V per cell, although for this application they should still be quite usable when they&#039;ve drained to 1.0V per cell.  So you have a supply voltage range of 4.0 - 4.8V.

I don&#039;t know how much electronics you know and how much you &lt;em&gt;want&lt;/em&gt; to know, but the supply voltage is going to be split between your LED(s) and your resistor.  Your LED specs say the LED will take 2.1V, so the remaining 1.9 to 2.7V (depending on battery charge) will fall across the resistor.

Now we want to calculate a resistor value that gives 25mA at 1.9 to 2.7V.  Given that I (current) = V (voltage) / R (resistance), you can rewrite to get R = V/I.  So

&lt;blockquote&gt;R = 1.9V / .025A = 76&#937;&lt;br/&gt;
R = 2.7V / .025A = 108&#937;&lt;/blockquote&gt;

So a 108&#937; resistor would be perfect when the NiMH cells are fully charged and a 76&#937; resistor would be perfect when they&#039;re a bit discharged.  If you want to run the LEDs at the full 25mA, I&#039;d compromise and use a widely-available 100&#937; resistor.

That said, I&#039;m guessing you &lt;em&gt;won&#039;t&lt;/em&gt; want the full 25mA / 6.3mcd.  I think you&#039;ll get lens flare on your videocamera at that brightness, and in my experience I think you&#039;ll actually want something closer to 10mA.  Assuming you can make sense of the equations above, I&#039;ll leave those calculations as an exercise for the reader. :-)  Plus you can always get some different sized resistors in the 100 - 1000&#937; range and just try them.</description>
		<content:encoded><![CDATA[<p>Zaid, the 4xAAA pack will be great for this &#8212; it&#8217;ll give you a lot longer life than the little coin cell I used.</p>
<p>Okay, let&#8217;s figure out the resistor.  First we need the battery voltage.  I&#8217;m going to assume you&#8217;ll be using NiMH rechargeables, both because you&#8217;ll be playing with this a lot and because they&#8217;re better for the environment.  They&#8217;re nominally 1.2V per cell, although for this application they should still be quite usable when they&#8217;ve drained to 1.0V per cell.  So you have a supply voltage range of 4.0 &#8211; 4.8V.</p>
<p>I don&#8217;t know how much electronics you know and how much you <em>want</em> to know, but the supply voltage is going to be split between your LED(s) and your resistor.  Your LED specs say the LED will take 2.1V, so the remaining 1.9 to 2.7V (depending on battery charge) will fall across the resistor.</p>
<p>Now we want to calculate a resistor value that gives 25mA at 1.9 to 2.7V.  Given that I (current) = V (voltage) / R (resistance), you can rewrite to get R = V/I.  So</p>
<blockquote><p>R = 1.9V / .025A = 76&Omega;<br />
R = 2.7V / .025A = 108&Omega;</p></blockquote>
<p>So a 108&Omega; resistor would be perfect when the NiMH cells are fully charged and a 76&Omega; resistor would be perfect when they&#8217;re a bit discharged.  If you want to run the LEDs at the full 25mA, I&#8217;d compromise and use a widely-available 100&Omega; resistor.</p>
<p>That said, I&#8217;m guessing you <em>won&#8217;t</em> want the full 25mA / 6.3mcd.  I think you&#8217;ll get lens flare on your videocamera at that brightness, and in my experience I think you&#8217;ll actually want something closer to 10mA.  Assuming you can make sense of the equations above, I&#8217;ll leave those calculations as an exercise for the reader. <img src='http://www.neufeld.newton.ks.us/electronics/wp-includes/images/smilies/icon_smile.gif' alt=':-)' class='wp-smiley' />   Plus you can always get some different sized resistors in the 100 &#8211; 1000&Omega; range and just try them.</p>
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		<title>By: Zaid</title>
		<link>http://www.neufeld.newton.ks.us/electronics/?p=129&#038;cpage=1#comment-22100</link>
		<dc:creator>Zaid</dc:creator>
		<pubDate>Tue, 05 Aug 2008 19:56:06 +0000</pubDate>
		<guid isPermaLink="false">http://www.neufeld.newton.ks.us/electronics/?p=129#comment-22100</guid>
		<description>Keith, the LEDs I&#039;m using are all green with the following specs: 2.1V - 25mA - 6.3mcd. I have a battery pack that holds four AAA batteries; also, i can make a pack myself with AA batteries, however, i would prefer using the pack since there is a switch and is already pre-made. 

I will follow your advice and use the parallel design with one external resistor. However, I&#039;m not sure how to calculate the amount of resistance i need for the circuit to work as intended. 

Thank You.</description>
		<content:encoded><![CDATA[<p>Keith, the LEDs I&#8217;m using are all green with the following specs: 2.1V &#8211; 25mA &#8211; 6.3mcd. I have a battery pack that holds four AAA batteries; also, i can make a pack myself with AA batteries, however, i would prefer using the pack since there is a switch and is already pre-made. </p>
<p>I will follow your advice and use the parallel design with one external resistor. However, I&#8217;m not sure how to calculate the amount of resistance i need for the circuit to work as intended. </p>
<p>Thank You.</p>
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		<title>By: Keith Neufeld</title>
		<link>http://www.neufeld.newton.ks.us/electronics/?p=129&#038;cpage=1#comment-22095</link>
		<dc:creator>Keith Neufeld</dc:creator>
		<pubDate>Sat, 02 Aug 2008 14:24:53 +0000</pubDate>
		<guid isPermaLink="false">http://www.neufeld.newton.ks.us/electronics/?p=129#comment-22095</guid>
		<description>Zaid, LEDs (almost) always need current-limiting series resistors.  I knew I could get away without them because the battery I was using was very low capacity -- it&#039;s described as having a high &quot;internal resistance&quot; -- that took the place of an external resistor, at least for a short-term demo.  But that&#039;s not necessarily how you want to do it for real.

What color LEDs are you using?  Different colors have different voltage drops, and I can show you how to calculate the resistor you&#039;ll want to use.  For this application, if you&#039;re using all the same color LEDs, I&#039;d suggest one resistor and all the LEDs in parallel behind it.  If different colors, probably a separate resistor for each.

The resistors will take care of the overheating problem, too.</description>
		<content:encoded><![CDATA[<p>Zaid, LEDs (almost) always need current-limiting series resistors.  I knew I could get away without them because the battery I was using was very low capacity &#8212; it&#8217;s described as having a high &#8220;internal resistance&#8221; &#8212; that took the place of an external resistor, at least for a short-term demo.  But that&#8217;s not necessarily how you want to do it for real.</p>
<p>What color LEDs are you using?  Different colors have different voltage drops, and I can show you how to calculate the resistor you&#8217;ll want to use.  For this application, if you&#8217;re using all the same color LEDs, I&#8217;d suggest one resistor and all the LEDs in parallel behind it.  If different colors, probably a separate resistor for each.</p>
<p>The resistors will take care of the overheating problem, too.</p>
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		<title>By: zaid</title>
		<link>http://www.neufeld.newton.ks.us/electronics/?p=129&#038;cpage=1#comment-22093</link>
		<dc:creator>zaid</dc:creator>
		<pubDate>Fri, 01 Aug 2008 18:52:03 +0000</pubDate>
		<guid isPermaLink="false">http://www.neufeld.newton.ks.us/electronics/?p=129#comment-22093</guid>
		<description>Thank you for the quick reply! Now that i know what i&#039;m looking for, i can get right on it. Excuse me for my ignorance, I have not worked with electronics before; I have been trying to create an LED glove like yours so i can do some image processing. I found your post very informative and if you don&#039;t mind i have a few more questions:

Would i need to calculate the amount of voltage i need, or should i find a battery holder like yours? (I need 6 LED lights on the glove, - one on the palm) Are resistors necessary?

What would be the best design for that many LEDs, series? parallel? a combination perhaps? 

I have noticed that the lights get hot quickly, do i need to worry about that or would the glove be enough protection?

Thank you very much for you time Keith.

P.S The link to Leah Buechley was very useful.</description>
		<content:encoded><![CDATA[<p>Thank you for the quick reply! Now that i know what i&#8217;m looking for, i can get right on it. Excuse me for my ignorance, I have not worked with electronics before; I have been trying to create an LED glove like yours so i can do some image processing. I found your post very informative and if you don&#8217;t mind i have a few more questions:</p>
<p>Would i need to calculate the amount of voltage i need, or should i find a battery holder like yours? (I need 6 LED lights on the glove, &#8211; one on the palm) Are resistors necessary?</p>
<p>What would be the best design for that many LEDs, series? parallel? a combination perhaps? </p>
<p>I have noticed that the lights get hot quickly, do i need to worry about that or would the glove be enough protection?</p>
<p>Thank you very much for you time Keith.</p>
<p>P.S The link to Leah Buechley was very useful.</p>
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		<title>By: Keith Neufeld</title>
		<link>http://www.neufeld.newton.ks.us/electronics/?p=129&#038;cpage=1#comment-22092</link>
		<dc:creator>Keith Neufeld</dc:creator>
		<pubDate>Fri, 01 Aug 2008 18:21:28 +0000</pubDate>
		<guid isPermaLink="false">http://www.neufeld.newton.ks.us/electronics/?p=129#comment-22092</guid>
		<description>Zaid, I&#039;m not sure about the gauge of the wire I used, although if I could find it, I could measure it with calipers.  Somewhere in the 30s.  And yes, I did use a fairly large needle, and sewed it just like thread (although being more careful not to tangle it).

It was wire made for winding magnetic coils of some sort, for transformers or instrument pickups.  If you like to salvage things, you could find a small transformer from inside a dead CRT monitor; or you might be able to use the 30-gauge wire from Radio Shack&#039;s &lt;a href=&quot;http://www.radioshack.com/product/index.jsp?productId=2036277&quot; rel=&quot;nofollow&quot;&gt;magnet wire assortment&lt;/a&gt;.

Also definitely check out the work of &lt;a href=&quot;http://www.cs.colorado.edu/~buechley/&quot; rel=&quot;nofollow&quot;&gt;Leah Buechley&lt;/a&gt;, a pioneer in making wearable circuits.  I know she has information somewhere on her site on the conductive thread she uses.</description>
		<content:encoded><![CDATA[<p>Zaid, I&#8217;m not sure about the gauge of the wire I used, although if I could find it, I could measure it with calipers.  Somewhere in the 30s.  And yes, I did use a fairly large needle, and sewed it just like thread (although being more careful not to tangle it).</p>
<p>It was wire made for winding magnetic coils of some sort, for transformers or instrument pickups.  If you like to salvage things, you could find a small transformer from inside a dead CRT monitor; or you might be able to use the 30-gauge wire from Radio Shack&#8217;s <a href="http://www.radioshack.com/product/index.jsp?productId=2036277" rel="nofollow">magnet wire assortment</a>.</p>
<p>Also definitely check out the work of <a href="http://www.cs.colorado.edu/~buechley/" rel="nofollow">Leah Buechley</a>, a pioneer in making wearable circuits.  I know she has information somewhere on her site on the conductive thread she uses.</p>
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		<title>By: zaid</title>
		<link>http://www.neufeld.newton.ks.us/electronics/?p=129&#038;cpage=1#comment-22091</link>
		<dc:creator>zaid</dc:creator>
		<pubDate>Fri, 01 Aug 2008 17:50:49 +0000</pubDate>
		<guid isPermaLink="false">http://www.neufeld.newton.ks.us/electronics/?p=129#comment-22091</guid>
		<description>This looks great. However, I&#039;m having trouble finding a wire that i can thread the glove with. Is there a specific size i should buy? Did you use a needle to sow it?
Thank You.</description>
		<content:encoded><![CDATA[<p>This looks great. However, I&#8217;m having trouble finding a wire that i can thread the glove with. Is there a specific size i should buy? Did you use a needle to sow it?<br />
Thank You.</p>
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		<title>By: Steve Wilson</title>
		<link>http://www.neufeld.newton.ks.us/electronics/?p=129&#038;cpage=1#comment-9092</link>
		<dc:creator>Steve Wilson</dc:creator>
		<pubDate>Mon, 09 Apr 2007 08:13:49 +0000</pubDate>
		<guid isPermaLink="false">http://www.neufeld.newton.ks.us/electronics/?p=129#comment-9092</guid>
		<description>&quot;So I trimmed it a little closer and more evenly around the fingertips, for better fit and comfort.&quot;

You know, I thought to myself the second I put the glove on, &quot;boy! this is the most comfortable, well-fitting LED glove I&#039;ve ever had the pleasure of wearing!&quot; Thank you for your consummate sartorial professionalism.</description>
		<content:encoded><![CDATA[<p>&#8220;So I trimmed it a little closer and more evenly around the fingertips, for better fit and comfort.&#8221;</p>
<p>You know, I thought to myself the second I put the glove on, &#8220;boy! this is the most comfortable, well-fitting LED glove I&#8217;ve ever had the pleasure of wearing!&#8221; Thank you for your consummate sartorial professionalism.</p>
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